Suppose an event C has a probability of 0.33, what is the P(C')? (Probability of not C)Give your answer as a decimal or percentP(C') = ?

Question

asked Apr 17, 2023 221k views

1 Answer

Erick Ramirez · Answer 1 · 2023-04-20T23:52:55+0000

Given:

Event C has a probability of 0.33

To find the probability of not C, we would need to apply the complement rule

The Complement Rule states that the sum of the probabilities of an event and its complement must equal 1, or for the event A:

$P\mleft(A\mright)+P\mleft(A^(\prime)\mright)=1$

Applying the complement rule:

$P(C)\text{ + P(C') = 1}$

Substituting the given values:

$\begin{gathered} 0.33\text{ + P(C') = 1} \\ \text{Collect like terms} \\ P(C^(\prime))\text{ = 1 - 0.33} \\ =\text{ }0.67 \end{gathered}$

Answer:

$P(C^(\prime))\text{ = 0.67}$