Question

What is the equation of the line that contains the point (2,3) and has a slope of - 3/2

Answer 1

equation of line

y=mx+b

If m=-3/2

we have

`\begin{gathered} y=mx+b \\ y=-(3)/(2)\cdot x+b \end{gathered}`

From points (2,3), we find b

`\begin{gathered} y=-(3)/(2)\cdot x+b \\ 3=-(3)/(2)\cdot2+b \\ 3=-3+b \\ b=6 \end{gathered}`

Therefore

`y=-(3)/(2)\cdot x+6`