Question

Find the variance of the following data. Round your answer to one decimal place. 6 7 8 9 10

Answer 1

The equation to find the variance is :

`s^2=\frac{\sum ^n_1(x-\bar{x})^2}{n-1}`

So, first we will find the mean of the given data

The given data are : 6 , 7 , 8 , 9 , 10

mean = (6+7+8+9+10)/5 = 8

Then find ( x - x')

Variance =

`\begin{gathered} ((6-8)^2+(7-8)^2+(8-8)^2+(9-8)^2+(10-8)^2)/(5-1) \\ \\ =((-2)^2+(-1)^2+(0)^2+(1)^2+(2)^2)/(5-1)=(4+1+0+1+4)/(4)=(10)/(4)=2.5 \end{gathered}`