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In 2014, the CDC estimated that the mean height for adult women in the U.S. was 64 inches with a standard deviation of4 inches. Suppose X, height in inches of adult women, follo…

In 2014, the CDC estimated that the mean height for adult women in the U.S. was 64 inches with a standard deviation of4 inches. Suppose X, height in inches of adult women, follo…
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In 2014, the CDC estimated that the mean height for adult women in the U.S. was 64 inches with a standard deviation of4 inches. Suppose X, height in inches of adult women, follows a normal distribution. Let x = 68, the height of a womanwho is 5'8" tall. Find and interpret the Z-score of the standardized normal random variable.

In 2014, the CDC estimated that the mean height for adult women in the U.S. was 64 inches-example-1
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User Ryan Chase
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\begin{gathered} Z-\text{score = }(X-X^i)/(\partial) \\ \text{Where X}^i=\operatorname{mean}\text{ and }\partial=\text{ standard deviation} \\ \text{From the information provided, } \\ X=68,X^i=64,\text{ }\partial=4 \\ Z-\text{score = }(68-64)/(4)\text{ = }(4)/(4)\text{ = 1} \end{gathered}

From the result, the correct answer is option A, that is the first option

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User Dimitar Nikovski
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