Question

F(x)= int 0 ^ x (t^ 3 +7t^ 2 +4) dt then

Answer 1

Since the given function is

`f(x)=\int_0^x(t^3+7t^2+4)dt`

That means

`f^(\prime)(x)=(t^3+7t^2+4)`

Then to find f''(x) we will differentiate f'(x) with respect to t

`\begin{gathered} f“(x)=3t^(3-1)+7(2)t^(2-1)+0 \\ \\ f“(x)=3t^2+14t \end{gathered}`

The answer is

`f“(x)=3t^2+14t`