Question

if a cube is rolled and recorded on a frquency table. how many times will it land on 3?the table is:number rolled: one| two | three| four| five| sixfrequency : 6 7 4 7 6 10

Answer 1

The sum of the frequency = 6+7+4+7+6+10=40

The number of times 3 occurred is = 4

Therefore the probability it will land on 3

`\begin{gathered} \frac{number\text{ of times 3 occurred}}{\text{total frequency}} \\ =(4)/(40) \\ =(1)/(10) \end{gathered}`