What is the mass in grams of carbon dioxide that would be required toreact with 80.5 g of LiOH in the following chemical reaction?2 LiOH(s) + CO,(g) – LiCO,(s) + H2O(1)

Question

asked Mar 17, 2023 86.8k views

1 Answer

Mohan Gopi · Answer 1 · 2023-03-23T09:34:03+0000

To solve this question we have to convert the given mass of litium hydroxide to moles using the molecular mass of this compound:

$80.5g\cdot(molLiOH)/(23.95g)=3.36molLiOH$

Now, use the stoichiometric ratio given by the chemical equation:

$3.36molLiOH\cdot(1molCO_2)/(2molLiOH)=1.68molCO_2$

Finally, convert the moles of CO₂ to g using the molecular mass of CO₂:

$1.68molCO_2\cdot(44g)/(molCO_2)=73.92g$

The mass of carbon dioxide required to react with 80.5g of LiOH is 73.92g.