Question

PLEASE HELP ON ASSESSMENT PRACTICE!!!!! URGENTLY PleaseHelp is much appreciated

Answer 1

Given the equation;

`y=5x^2+20x-1`

so, by completing the square the equation will be:

`\begin{gathered} y=5(x^2+4x)-1 \\ y=5(x^2+4x+4)-1-20 \\ y=5(x+2)^2-21 \\ \\ y=5(x-(-2))^2-21 \end{gathered}`

So, the vertex of the equation will be at ( -2 , -21 )

So, the equation of the axis of symmetry is:

`x=-2`