Question

On a standardized exam, the scores are normally distributed with a mean of 79 and a standard deviation of 20. Find the z-score of a person who scored 121 on the exam.

Answer 1

z = 2.1

Explanation:

`z=(x-\mu)/(\sigma)\\ \\z=(121-79)/(20)\\ \\z=(42)/(20)\\ \\z=2.1`

This tells us that the person's score of 121 places them 2.1 standard deviations above the mean score of 79.