Question

an observer recorded the following data for the motion of a car undergoing constant acceleration from 3.0 seconds to 5.0 seconds. What was the magnitude of the car's acceleration ?

Answer 1

The acceleration is given as:

`a=(v_f-v_0)/(t_f-t_0)`

Using the first two rows we have:

`a=(6-4)/(4-3)=(2)/(1)=2`

Therefore the acceleration is 2 meter per second per second.