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Evaluate the following for h(25). h(n)=4n +32

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User Dcmorse
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1 Answer

3 votes

h(n)=4n+32

When the function is written in the form h(n) it means that for every value in n there will be a different value in h.

to find h(25) we must replace n for 25 in the equation.


\begin{gathered} h(25)=4\cdot(25)+32 \\ h(25)=100+32 \\ h(25)=132 \end{gathered}

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User Die In Sente
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