Question

F(x)=1/4x^2+bx+10 is x=6. what is the value of b

Answer 1

Given the equation

`f(x)=(1)/(4)x^2+bx+10`

For x=6 you have to determine the value of b

To do so, equal the function to zero and replace the variable x with the given number:

`\begin{gathered} (1)/(4)(6)^2+6b+10=0 \\ 9+6b+10=0 \\ 6b+19=0 \\ 6b=-19 \\ (6b)/(6)=-(19)/(6) \\ b=-(19)/(6) \end{gathered}`