Question

Find the element that is oxidized and the one that is reduced 2 CuSO4 + 4 KI --> 2 CuI + 2 K2SO4 + I2

Answer 1

This is an oxidation-reduction (redox) reaction:

2 Cu² + 2 e- → 2 Cu¹ (reduction)

2 I⁻¹ - 2 e- → 2 I⁰ (oxidation)

CuSO₄ is an oxidizing agent, KI is a reducing agent. Therefore Copper is being reduced and Iodine oxidized.