Question

Pretty sure answer is 37 degrees just want a quick check to be sure

Answer 1

Given :

`\begin{gathered} AD\parallel BC \\ EB\parallel DC \\ \angle BAE=90^(\circ) \\ \angle ABE=53^(\circ) \end{gathered}`
`\begin{gathered} \Delta ABE \\ \angle AEB+\angle EAB+\angle EBA=180^(\circ) \\ \angle AEB+90^(\circ)+53^(\circ)=180^(\circ) \\ \angle AEB=180^(\circ)-143^(\circ) \\ \angle AEB=37^(\circ) \end{gathered}`

AS EB is parallel to DC

From corresponding angles

`\begin{gathered} \angle AEB=\angle EDC \\ =37^(\circ) \end{gathered}`

Thus, the required value of angle is 37.