Question

In how many different ways can a nickel, a dime and a quarter be given to four children if one coin is given to each child

Answer 1

In this case, we have to use permutations to solve this problem, we have 3 options for 3 positions, use permutation this way:

`\begin{gathered} 3P3=(3!)/((3-3)!) \\ 3P3=(3!)/(0!)=6 \end{gathered}`

The coins can be given in 6 different ways.