Question

How would I find the area of a trapezoid whose bases are x and 3x+4 and height is x+2

Answer 1

Area of Trapezium.

By formula,

`\begin{gathered} \text{Area =}(1)/(2)(a\text{ + b)h} \\ \text{Where a =x , b = 3x+4 , and h = x + 2} \\ \text{Area =}(1)/(2)(x+3x+4)(x+2) \\ \text{Area =}(1)/(2)(4x+4)(x+2) \\ \\ \text{Area = }(1)/(2)*4(x+1)(x+2)\text{ =2(x+1)(x+2)} \end{gathered}`

So, the correct answer is 2(x+1)(x+2)