Question

Y=-16x^2+248x+116 round to the nearest 100th of second

Answer 1

We have the expression:

`y=16x^2+248x+116`

We now, solve using the quadratic function:

`x=\frac{-(248)\pm\sqrt[]{(248)^2-4(16)(116)}}{2(16)}`

Now, we will have that x has the following values:

`x\approx-0.48`

and:

`x\approx-15.02`