Question

I'm confused on how to set this up. the unit is on Trigonometry and Right Triangles if it helps

Answer 1

We get thatb

`\tan 60=\frac{16\sqrt[]{3}}{x}\rightarrow x=\frac{16\sqrt[]{3}}{\tan 60}=16`
`\sin 60=\frac{16\sqrt[]{3}}{y}\rightarrow y=\frac{16\sqrt[]{3}}{\sin 60}=32`