Question

Find the equation for the line through points (-9,2) and (3,5) use y=Mx+b

Answer 1

`M=(y2-y1)/(x2-x1)\text{ (1)}`
`M=(5-2)/(3-(-9))=(3)/(12)=(1)/(4)`

now we are going to find b

`b=y-Mx`

we are going replace (3,5) in the last equation

`b=5-(1)/(4)\cdot3`
`b=5-(3)/(4)=(17)/(4)`

the equation is

`y=(1)/(4)x+(17)/(4)`