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2 votes
Prove if n is even then n^3 is even

asked
User Haroldo
by
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1 Answer

3 votes

since n is even

we can express an even number as


2k=n

then


n^3=(2k)^3
n^3=8k^3
2(4k^3)

and since this number is multiple of 2 then we can prove that n^3 is even

answered
User Nikola
by
7.5k points

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