Question

a bag contains seven green Marbles and four white marbles. You select a marble at random. What are the odds in favor of picking a green marble.1) 7:112) 7:43) 4;74)3:7these are the options for answer

Answer 1

There are seven green marbles and four white ones; therefore, there are 7+4=11 marbles in the bag. Then, the odds of drawing a green marble are

`\begin{gathered} odds=(probability)/(1-probability) \\ \Rightarrow odds(green)=((7)/(11))/(1-(7)/(11))=((7)/(11))/((4)/(11))=(7)/(4) \end{gathered}`

Written as a ratio,

`\Rightarrow odds(green)=7:4`

Thus, the answer is 7:4, option 2.