A horizontal force of 30 N just starts to move a 9kg object. Findthe value of coefficient of static friction and angle of friction.

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asked Jun 2, 2023 45.9k views

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Ruchi · Answer 1 · 2023-06-09T14:09:43+0000

Use the static friction formula.

$\begin{gathered} \mu_s=(F)/(mg)=\frac{30N}{9\operatorname{kg}\cdot9.8\cdot(m)/(s^2)} \\ \mu_s=0.34 \end{gathered}$

Therefore, the coefficient of static friction is 0.34. The angle of friction would be 180 because it's opposite to the direction of the movemNo ent.

A horizontal force of 30 N just starts to move a 9kg object. Findthe value of coefficient of static friction and angle of friction.

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