Question

Math help pleaseeeeeeeeeeeee. solving the triangle side values not in degree form

Answer 1

Given;

`C=90^o,A=52^o,b=219m`

Thus;

We would apply the tangent ratio given as;

`\begin{gathered} \tan\theta=(opposite)/(adjacent) \\ \\ \tan52^o=(BC)/(219) \\ \\ BC=219\tan52^o \\ \\ BC=280.3m \end{gathered}`

Also;

`\begin{gathered} \cos\theta=(adjacent)/(hypotenuse) \\ \\ \cos52^o=(219)/(AB) \\ \\ AB=(219)/(\cos52^o) \\ \\ AB=355.7m \end{gathered}`