asked 218k views
2 votes
Which function is shown in the graph?36-9OAA. V=30О в.= 3 + 6x1-x6xO c. 1+xOD. V=2+xy=12SUBMIT

Which function is shown in the graph?36-9OAA. V=30О в.= 3 + 6x1-x6xO c. 1+xOD. V=2+xy-example-1
asked
User SubSevn
by
7.7k points

1 Answer

1 vote

The graph shows no vertical or horizontal asymptotes. Instead, the asymptote seems to be oblique or slanted. This indicates that the degree of the numerator must be the same as the degree of the denominator.

The removes the first option as a possible answer.

To simplify the solution, you may take up any point on the graph whose coordinates you can clearly identify. Let's take (0, 3).

Let's check if any of the remaining equations contain the point (0, 3).


\begin{gathered} y=(3+6x)/(1-x) \\ \\ 3=(3+6(0))/(1-0) \\ \\ 3=3\text{ TRUE} \end{gathered}
\begin{gathered} y=(6x)/(1+x) \\ \\ 3=(6(0))/(1+0) \\ \\ 3=0\text{ FALSE} \end{gathered}
\begin{gathered} y=(2+x)/(1-x) \\ \\ 3=(2+0)/(1-0) \\ \\ 3=2\text{ FALSE} \end{gathered}

Because it is only true for the second option, then the equation must be y = (3 + 6x)/(1 - x).

Which function is shown in the graph?36-9OAA. V=30О в.= 3 + 6x1-x6xO c. 1+xOD. V=2+xy-example-1
answered
User DMEM
by
7.9k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.