Question

In one baseball season, Peter (p) hit twice the number of homeruns that Mark (m) hit. Together they hit 18 homeruns. How many homeruns did each person hit?

Answer 1

Given that in one baseball season, Peter (p) hit twice the number of homeruns that Mark (m) hit. This can be interpreted algebraically as shown below:

`p=2m`

Also, given that together they hit 18 homeruns. This can be interpreted as shown below:

`p+m=18`

Substitute p = 2m in the total home runs to know the home runs each person hit as shown below:

`\begin{gathered} p+m=18,p=2m \\ 2m+m=18 \\ 3m=18 \\ \text{divide through by 3} \end{gathered}`
`\begin{gathered} (3m)/(3)=(18)/(3) \\ m=6 \end{gathered}`

Substitute for m in p= 2m to p as shown below:

`\begin{gathered} p=2m,m=6 \\ p=2*6 \\ p=12 \end{gathered}`

Hence, Peter hits 12 homeruns and Mark hits 6 homeruns