Question

PART C a right triangle is shown below with an altitude drawn from the right angle to the hypotenuse prove that triangles ABC, ADB and BDC are all similar

Answer 1

given the figure

Similar triangles are given by definition when the inner angles of one triangle

are the same as the second triangle

given the angles between parallels theorems

then

then

since the triangle ADB have the same inner angles of BDC

where the angles of the triangle

ADB

∠A

∠D

∠B

are equal to the angles of the triangle

BDC

∠B

∠D

∠C

correspondingly

and they are equals to the angles in the triangle

ABC in the angles

∠A

∠D

∠C

correspondingly