Question

Is my answer correct? if not can you please tell me the right one and why it is wrong?

Answer 1

1.0

Explanation:

To find the variance of the probability distribution, we make use of the formula:

`\sigma^2=\sum x^2P(x)-\mu^2`

First, find the expected value, i.e mean of the distribution.

`\mu=\sum xP(x)`

From the table, the mean of the distribution = -0.60.

Next, we find the variance.

From the table:

`\sum x^2P(x)=1.36`

Therefore:

`\implies\sigma^2=\sum x^2P(x)-\mu^2=1.36-(-0.60)^2=1.36-0.36=1`

The variance of the probability distribution is 1.0