Question

Write the equation of the circle centered at (6, 3) with radius 6

Answer 1

`(x-6)^2+(y-3)^2=36`

Step-by-step explanation:

If the equation of a circle is given by

`(x-a)^2+(y-b)^2=r^2`

then the circle is centred at (a, b) and the radius is r.

Now in our case, we know that (a, b) = (6, 3) and r = 6; therefore, the above equation gives

`(x-6)^2+(y-3)^2=6^2`

which can also be written as

`\boxed{\left(x-6\right)^2+\left(y-3\right)^2=36.}`

which is our answer!