Question

What is the solution when the equation wx^2+w=0 is solved for x, where w is a positive integer?1.-12.03.64. ±i

Answer 1

Given equation is

`wx^2+w=0`

Here w is a positive integer.

Now, from the given equation

`\begin{gathered} wx^2+w=0 \\ w(x^2+1)=0 \\ x^2+1=0\text{ \lbrack{}as w is a positive integer\rbrack} \\ x^2=-1 \\ x=\pm i\text{ i=}\sqrt[]{-1} \end{gathered}`

Hence, the correct option is (4).