Question

hey I need help solving this problem. it's the pythagorean theorem. A=7 B=8 and I need to find what C is to the nearest Tenth

Answer 1

`\begin{gathered} A^2+B^2=C^2 \\ 7^2+8^2=C^2 \\ 49+64=C^2 \\ C^2=113 \\ C=\sqrt[]{113} \\ \\ C=10.630145 \\ \\ C\approx10.6 \end{gathered}`