Question

About 9% of the population has a particular genetic mutation. 700 people are randomly selected.Find the standard deviation for the number of people with the genetic mutation in such groups of 700. Round your answer to two decimal places.

Answer 1

Given:

n = 700

p = 0.09

q = 1 - p = 0.91

The formula for standard deviation is:

`σ=(npq)^{(1)/(2)}`

hence:

`\begin{gathered} σ=(700*0.09*0.91)^(1/2) \\ σ=7.57 \end{gathered}`

ANSWER

σ ≈ 7.57