Question

Find the equation of the line through the point (8,-10) that is perpendicular to the line with slope -3/2

Answer 1

`y=(2)/(3)x-(46)/(3)`

Explanation:

A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line. Therefore, the slope of the line is -(-2/3)=2/3.

Therefore, for the given line using the slope-point form of the equation:

`\begin{gathered} y+10=(2)/(3)(x-8) \\ y=(2)/(3)x-(16)/(3)-10 \\ y=(2)/(3)x-(46)/(3) \end{gathered}`