Question

I need help and the teacher isnt good at explaining

Answer 1

We are given the following equation

`y=mx+b`

We are also given the following values

`\begin{gathered} y=5 \\ m=(1)/(2) \\ x=4 \end{gathered}`

Let us substitute these values into the given equation and solve for b

`\begin{gathered} y=mx+b \\ 5=(1)/(2)\cdot4+b \\ 5=(4)/(2)+b \\ 5=2+b \\ 5-2=b \\ 3=b \\ b=3 \end{gathered}`

Therefore, the value of b is 3