Question

What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?

Answer 1

The radioactive half-life is given by:

`T_(1/2)=(ln(2))/(\lambda)`

Where:

`\begin{gathered} T_(1/2)=299*10^(-9)s \\ so: \\ \lambda=(ln(2))/(299*10^(-9)) \\ \lambda=2.32*10^6s \end{gathered}`