Question

Answer the questions below about the quadratic function. f(x) = 2x ^ 2 - 20x + 49

Answer 1

`f(x)=2x^2-20x+49`

Since the leading term has a positive coefficient, the function is concave up and has a minimum value.

The minimum value of the quadractic function is given by:

`-(b^2-4ac)/(4a)=-((-20)^2-4\cdot2\cdot49)/(4\cdot2)=-1`

This minimum value occur at:

`-(b)/(2a)=-((-20))/(2\cdot2)=5`