Question

(RLT.G.2.b, 1 pt) Lines r and s are cut by a transversal. Solve for the value of x that proves that r | s ? 1435 (3r +14)°

Answer 1

x = 43 degrees.

Corresponding angles are equal

3x + 14 = 143

collecting the like terms

3x = 143 - 14

3x = 129

divide both sides by 3

x = 129/3

x = 43 degrees