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Find the length of the altitude of an isosceles triangle with a 64° vertex angle and a base 48 cm long. Round your answer to the nearest tenth.

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User Ziggy
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1 Answer

4 votes

Therefore,


\begin{gathered} \tan (32^0)=(24)/(h) \\ \text{thus} \\ h=(24)/(\tan(32^0))=38.4\operatorname{cm} \end{gathered}

Therefore the length of the altitude is 38.4cm

Find the length of the altitude of an isosceles triangle with a 64° vertex angle and-example-1

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