Question

Solve tan x + 1 = 0 on the interval [0, 2n).Ο π 5π4' 4π 5π6' 63π43π3π 7π44.

Answer 1

The question is given by:

`\tan x+1=0`
`\lbrack0.2\pi)`

The solution is given by:

`\tan x=-1`

Now this value is possible only if

`x=(3\pi)/(4),(7\pi)/(4)`

So the answer is option D