Question

Note: Triangle may not be drawn to scale.Suppose a=48 and b=55 and c=73.sec(B)=csc(B)=cot(B)=

Answer 1

First, we need to know if we have a right triangle using the Pythagorean theorem

`c=\sqrt[]{a^2+b^2}`

If we substitute the values of a and b and we obtain the value given of c we have a right triangle

`c=\sqrt[]{48^2+55^2}=73`

As we can see we have a right triangle

Then we can calculate the

`\sec (B)=(1)/(\cos (B))=(1)/((48)/(73))=(73)/(48)`
`\csc (B)=(1)/(\sin (B))=(1)/((55)/(73))=(73)/(55)`
`\cot (B)=(1)/(\tan (B))=(1)/((55)/(48))=(48)/(55)`