Question

Weights Pounds12.90 $17.1518.20 $23.7720.50 $26.7216.40 $19.8715.40 $23.2210.60 $9.14A. Find the numerical value for correlation between weight and pounds B. Report the equation of the best straight line as predictor (x) and the cost as (y)C. Report the slope and interception of the regression line and explain what it shows. If the intercept is not appropriate, explain D. Report the slope of the regression line and explain what it shows

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

table

Step 02:

data table:

graph:

point 1 (15 , 19)

point 2 (20, 26)

slope = m:

`m\text{ =}(y2-y1)/(x2-x1)=((26-19))/((20-15))=(7)/(5)=1.4`

slope = m = 1.4

point-slope form of the line:

(y - y1) = m (x - x1)

(y - 19) = 1.4 (x - 15)

y - 19 = 1.4x - 21

y = 1.4x - 21 + 19

y = 1.4x - 2

equation of the line:

y = 1.4x - 2

slope :

is the variation of the price depending on the weight

y-intercept:

x = 0;

y = 1.4x - 2

y = 1.4(0) - 2

y = - 2

y-intercept = - 2

y-intercept:

when the weight is equal to zero the price is $ -2

it would be more logical for the price to be zero when the weight is zero

That is the full solution