Question

Factor: x²-xy-3x+2+2y

Answer 1

Given the expression:

`x^(2)-xy-3x+2+2y​`

We will factor the expression as follows:

`\begin{gathered} x^(2)-xy-3x+2+2y​ \\ =(x^2-3x+2)+(-xy+2y) \\ =(x-2)\cdot(x-1)-y(x-2) \\ =(x-2)\cdot(x-y-1) \end{gathered}`

so, the answer will be:

`(x-2)(x-y-1)`