Question

Find the area to the right of x=60 under a normal distribution curve with the mean=71 and standard deviation=6.

Answer 1

Given that:

Mean = 71

Standard deviation = 6

To find

`P(X>60)`

The Z-score for X is

`Z=(X-\mu)/(\sigma)`

Thus,

[tex]\begin{gathered} P(X>60)=P(Z>\frac{60-71}{6}) \\ =P(Z>-1.83) \\ =0.5+P(0From the standard normal table, P(0