Question

Hi, can you help me to solve this exercise, please!

Answer 1

Use the next trigonometric ratio for angle 60º in a right triangle:

`\cos 60º=\frac{\text{adjacent leg}}{hypotenuse}=(WX)/(YX)`

Use the given data to solve WX:

`\begin{gathered} \cos 60º=\frac{WX}{6\sqrt[]{3}} \\ \\ WX=6\sqrt[]{3}*\cos 60 \\ \\ WX=6\sqrt[]{3}*(1)/(2) \\ \\ WX=\frac{6\sqrt[]{3}}{2} \\ \\ WX=3\sqrt[]{3} \end{gathered}`Then, WX is:
`WX=3\sqrt[]{3}`