Question

Find the amplitude and period of the function: () = −2 sin

Answer 1

For a function of the form:

`f(x)=A\sin (bx)`

Where:

A = Amplitude

b = Angular frequency

The period is given by:

`\begin{gathered} T=(2\pi)/(b) \\ \end{gathered}`

Therefore:

`\begin{gathered} T=(2\pi)/(1)=2\pi \\ and \\ A=-2 \end{gathered}`