Question

Write the quadratic equation in standard form:-4x – 19 = x2

Answer 1

We have the following solution:

`x^2+4x+19=0`

And we can use the following equation:

`x=\frac{-\text{b}\pm\sqrt[]{b^2-4ac}}{2a}`

For this case a=1, b=4, c=19

Replacing we got:

`x=\frac{-4\pm\sqrt[]{(4)^2-4(1)(19)}}{2(1)}=\frac{-4\pm\sqrt[]{-60}}{2}=-2\pm\sqrt[]{15}i`

Then the answers are:

`x=-2-\sqrt[]{15}i,-2+\sqrt[]{15}i`