Question

Find the area of the given rhombus if BD=10 and BC=13

Answer 1

`\text{Area of Rhombus = }(1)/(2)*\text{ diagonal 1}*\text{ diagonal2}`

we will need to find x, using Pythagoras theorem, we have

`\begin{gathered} \text{hyp}^2=opp^2+Adj^2 \\ 13^2=5^2+x^2 \\ 169=25+x^2 \\ 169-25=x^2 \\ 144\text{ =}x^2 \\ x^2\text{ = 144} \\ x\text{ = }\sqrt[]{144} \\ x\text{ = 12} \\ \end{gathered}`
`\begin{gathered} \text{Diagonal 1 = 10} \\ \text{Diagonal 2 = 12+ 12 = 24} \\ \text{Area =}(1)/(2)*10*24 \\ \text{Area =}(240)/(2)=120u^2 \end{gathered}`