Question

A fan ratones at a rate of 2400 RPM calcular periodfrequency

Answer 1

The RPM of the fan is 2400.

The angular velocity can be determined as,

`\begin{gathered} \omega=(2\pi N)/(60) \\ =(2*\pi*2400)/(60) \\ =80\pi\text{ rad/s.} \end{gathered}`

The time period can be determined as,

`\begin{gathered} T=(2\pi)/(80\pi) \\ T=(1)/(40) \\ T=0.025\text{ s} \end{gathered}`

Thus, the required time period is 0.025 seconds.

The frequency can be determined as,

`\begin{gathered} f=(1)/(T) \\ =(1)/(0.025) \\ =(1000)/(25) \\ =40\text{ Hz} \end{gathered}`

Thus, the required frequency is 40 hertz.