Question

What is the point of instruction when the system of equations below is graphed on the cordinate plane?

Answer 1

To solve the given system, we have to multiply the first equation by -1.

`\begin{cases}x-y=-4 \\ 6x+y=-3\end{cases}`

Then, we combine the equations

`\begin{gathered} 6x+x+y-y=-4-3 \\ 7x=-7 \\ x=-(7)/(7) \\ x=-1 \end{gathered}`

Now, we find y

`\begin{gathered} x-y=-4 \\ -1-y=-4 \\ -y=-4+1 \\ -y=-3 \\ y=3 \end{gathered}`

Hence, the intersection point is (-1,3).