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In how many different ways can 3 people select seats at adining table having 8 seating positions if they can select anyseat?

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SOLUTION


\begin{gathered} The\text{ three people can be selected for the 8 seats using the combination } \\ in\text{ the form of } \\ ^8C_3 \end{gathered}
\begin{gathered} ^8C_3\text{ = }(8!)/((8-3)!3!) \\ \\ =\text{ }(8*7*6*5!)/(5!*3*2) \\ \\ =(336)/(6) \\ \\ =\text{ 56 ways } \end{gathered}

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