Question

How do you solve quadratic using square roots?ex: 2(x+2)²-5=8

Answer 1

For the problem given, we will take all the constants to the right hand side and take square root of both sides and solve for the potential value(s) of x. The step by step process is shown below:

`\begin{gathered} 2(x+2)^2-5=8 \\ 2(x+2)^2=8+5 \\ 2(x+2)^2=13 \\ (2(x+2)^2)/(2)=(13)/(2) \\ (x+2)^2=(13)/(2) \\ \sqrt[]{(x+2)^2}=\sqrt[]{(13)/(2)} \\ x+2=\pm\sqrt[]{(13)/(2)} \\ x=\pm\sqrt[]{(13)/(2)}-2 \end{gathered}`

The two answer(s) for the problem shown are:

`\begin{gathered} x=\sqrt[]{(13)/(2)}-2 \\ x=-\sqrt[]{(13)/(2)}-2 \end{gathered}`